-4.9x^2+24.75x=0

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Solution for -4.9x^2+24.75x=0 equation:



-4.9x^2+24.75x=0
a = -4.9; b = 24.75; c = 0;
Δ = b2-4ac
Δ = 24.752-4·(-4.9)·0
Δ = 612.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24.75)-\sqrt{612.5625}}{2*-4.9}=\frac{-24.75-\sqrt{612.5625}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24.75)+\sqrt{612.5625}}{2*-4.9}=\frac{-24.75+\sqrt{612.5625}}{-9.8} $

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